ext_59053 (
bellinghman.livejournal.com
) wrote
in
attimes_bracing
2014-05-22 12:11 pm (UTC)
no subject
Waaaah!!
Oh well, that means
If z = 0
x + 4y -> 25
x + y -> 8
And 3y -> 15, so y -> 5
Can't fit 5 2x2s in, so that fails
If z = 1, then
x + 4y -> 16
x + y -> 7
And therefore 3y -> 9. Promising. y -> 3
Yep, One 3x3, 3 2x2s beside it, and you end up with 4 1x1 squares. Lots of permutations, none difficult to make
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no subject
Oh well, that means
If z = 0
x + 4y -> 25
x + y -> 8
And 3y -> 15, so y -> 5
Can't fit 5 2x2s in, so that fails
If z = 1, then
x + 4y -> 16
x + y -> 7
And therefore 3y -> 9. Promising. y -> 3
Yep, One 3x3, 3 2x2s beside it, and you end up with 4 1x1 squares. Lots of permutations, none difficult to make