Date: 2014-05-22 12:11 pm (UTC)
Waaaah!!

Oh well, that means

If z = 0

x + 4y -> 25
x + y -> 8

And 3y -> 15, so y -> 5

Can't fit 5 2x2s in, so that fails

If z = 1, then

x + 4y -> 16
x + y -> 7

And therefore 3y -> 9. Promising. y -> 3

Yep, One 3x3, 3 2x2s beside it, and you end up with 4 1x1 squares. Lots of permutations, none difficult to make
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